Take note of whether it is heavier or lighter. The ice cube and the basketball have the same weight. 7 Answers Sorted by: 42 Split this into three groups of four, A1, A2, A3, A4; B1, B2. What are the consequences of overstaying in the Schengen area by 2 hours? ((, Please explain your claim that is was not asked properly. If the seesaw balances we know that either 1 or 2 or 3 is oddly weighted. If not balanced, the one going down is heavy. How do you do it? In either scenario, the steps are basically the same. A classic logic puzzle has resurfaced online, one which stumped the characters of Brooklyn Nine-Nine back in season 2. Solution 1a. Weigh the lighter of the 2 men against any other neutral man. Can you solve the classic 12 marbles riddle? Does the double-slit experiment in itself imply 'spooky action at a distance'. Thanks! There is also a see-saw on the island. If one is heavier they are the odd one otherwise it is 6. Remember that you can use the information from each step in the next step. seesaw: S1 S2 S3 R1 R2 R3 (balanced) IF the measurement is equal then the odd man is 12. So in principle, we should be able to solve the problem. we weigh S1 against S2; if balanced it is S3 - else it is the heavy of S1 and S2. Thanks, AeJey for making it so clear! Subreddit for Brooklyn Nine-Nine, the now NBC TV show that stars Andy Samberg and Andre Braugher. Use Git or checkout with SVN using the web URL. Note : I am not looking for a new way to solve this. ; C1, C2. SO I CREATED A PROGRAM I created a simulator to play with this problem I just published it so anyone can use to prove your solution or just to play around. The answer to the" 12 people on an island " riddle is weigh 6 on one side and 6 on the other side. Now we know that the different man is among {9,10,11,12}. Hope you all sleep well after reading this. Scenario Two, from your original 4x4 weighing: 2. Solution: The minimum number of times seesaw will be needed is 3. The island has no escapes, but there is a see-saw. I like Rosa's answer squeeze until fatty confesses. 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. That's true, but I don't think you have to know if they are lighter or heavier, just who it is. Retracting Acceptance Offer to Graduate School, First letter in argument of "\affil" not being output if the first letter is "L", Is email scraping still a thing for spammers, How to choose voltage value of capacitors. The riddle, as you'll recall, is this: There are twelve men on an island. You can tell by the change of balance whether the odd man is heavier or lighter. Wow how did this even get 8 upvotesmind boggling. Now you know that one of the four men on one side is light. There is a seesaw to determine who is the odd one out. I was lying there going through possibilities until 3 am when it hit me, and I got up and wrote down the solution. sideline: S1 S2 S3 S4. Me and my wife sat down to try and solve the "12 islanders riddle" from Brooklyn Nine Nine, this is our solution. Are you sure you want to create this branch? sorry my bad. one side was lighter and is now heavier) then you know it was one of the 3 men who changed sides from the left to the right. 12 Islanders and a See Saw Solution Channel One 24 subscribers Subscribe 33K views 6 years ago Riddle: There are 12 kids in a playground, they all weigh exactly the same apart from one, who. But this is simple! Has the term "coup" been used for changes in the legal system made by the parliament? Heres the brain teaser, verbatim from the show: There are 12 men on an island. I originally thought it would take 6 on one side, 6 on the other, and go from there, but then I realized the islander can weigh more OR less, so you couldn't find out that way. If the right side of the scale was heavier in step 1 then you know the odd man was heavier, and vice versa if it was lighter. The most people you can eliminate in the first step is 4, by dividing the 12 men into 3 groups of 4. we now know that the heavier islander are amongst S1 S2 S3. Each islander is given a position to sit on the seesaw for each round. This way of wording will help make it easier to figure out the puzzle. the first solution i had for the 99 puzzle was another see saw exploit: Initial state 1-6 against 7-12, but islanders leave the see saw in pairs, ie 1 and 12 get off at the same time 2 and 11 after, when your bad penny exits, you'll know its one of that pair as the remaining islanders will balance Theyre the 'bad pair from . to use Codespaces. You have to figure out which Islander is the heaviest using a seesaw. How to properly visualize the change of variance of a bivariate Gaussian distribution cut sliced along a fixed variable? There are 12 men on an island. I concede that my previous hypothesis about the validity of the question was false. Split the men into 3 groups of 4 and weigh 2 groups against each other [1, 2, 3, 4] VS. [5, 6, 7, 8]. If the see saw is not balanced, remove one from each end. Proceed to solution 2a. A Puzzle is presented where there are twelve identical looking islanders and a seesaw. neutral islander to figure out if it is heavy or light. However only three measurements are allowed. (First Use). Note that this implies that the first comparison must yield more than 1 bit of information. Pardon the handwriting, its usually better. Can a VGA monitor be connected to parallel port? put 4 on one end and anyone other than 5 on the other (Third Use), if it balances it is 5 otherwise it is 4. What are some tools or methods I can purchase to trace a water leak? c) If they are the same, then one of 3,4 is different. Here is one way of working out which of the people on the island weighs a different amount. -v, 1 split the 12 islanders into three groups After each round, we can see if the seesaw tilted down on the left (L), right (R) or was balanced (-), The pattern of the seesaw will match the pattern of one person ( or be exactly reversed ). At this point we just weight S4 against a Here is a more precise retelling of the riddle we found. seesaw: R1 L2 L3 L4 L1 S2 S3 S4 (heavy) Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. Why are non-Western countries siding with China in the UN? This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. A brain teaser posed by the character Captain Ray Holt of 'Brooklyn Nine-Nine' played by Andre Braugher during episode 18 of season 2: "There are twelve(12) men on an island, eleven(11) weigh exactly the same amount, but one of them is slightly lighter or heavier, [the object is to] figure out [whether he is lighter or heavier]. 11 of them weigh the same and one of them is either slightly If these are equal, the different man is 12. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. SPOILER ALERT! The kid sitting on the end is the load. Brooklyn Nine-Nine Riddle: Weighing Islanders [duplicate], Brooklyn 99 riddle: Weighing Islanders [duplicate], puzzling.stackexchange.com/questions/9979/, puzzling.stackexchange.com/questions/183/. put A&B on the seesaw then put A&C ( 2 uses) logic will give you the answer. now switch R1 R2 R3 and S2 S3 S4 AND switch R1 AND L1. WRONG! The island has no escapes, but there is a seesaw. Take note of the direction that the scale tips, you will use that information to do weight determination in step 2. Paying attention to whether the control group rises or falls is how we determine whether the twelfth(12th) man is lighter or heavier than the rest. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. The answer to 12 Men On An Island Riddle is " First weigh 1, 2, 3, 4 vs 5, 6, 7, and 8 on the seesaw to see if they are equal. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. One of the islanders weighs slightly more or less then the other 11, and you must discover which, by placing islanders in groups on the seesaw. You don't know heavier or lighter, but you still have 1 remaining move. There is also a see-saw on the island. Thus in principle we can get log 2 27 bits from the three comparisons. There is an island with 12 islanders. Similar logic will help us design all further comparisons. You can weigh three combinations of men on the see-saw. Eleven weigh exactly the same amount, but one of them is slightly lighter or heavier. If A > B, then weigh A1, B1, and B2 against B3, B4, and C1. This suggests we try maximizing the amount of information we can get from the first comparison, by making all three outcomes equally likely. In other news,did Pete Davidson tattoo a kid? What is the answer to the seesaw riddle? 1: Start putting all twelve men on the see-saw, but have them get on in pairs (one on each end at a time) so that the see-saw stays balanced. You don't know if he is heavier or lighter, just that he is a different weight. Find out the minimum number of times the seesaw will be used. Weigh 9,10,11 against 1,2,3. Before you read on, I just want to say that this problem drove me nuts. Have something to tell us about this article? A tag already exists with the provided branch name. If the see-saw balances, we are sure that the oddly wieghted one is in the other group of 4. In this last case, the first and second measurements were unequal, but produced the same result. Thats really not conducive to Andy Samberg zingers. It is easier than everyone makes it. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. 11 of them weigh the same and one of them is either slightly heavier or slightly lighter. Weigh them against each other. [10, 11, 12, 1] VS. [2, 3, 4, 5]. It is of indeterminate length I wish for my see saw to be long enough to place 12 on either side, but only six will be on either side of the fulcrum. Use the weight difference from step 1 to determine heavier lighter. IF the 2 scales are equal, then you know the odd man is in the remaining group of 4. Please (Third Use), If the see saw is not balanced, remove one from each end. There you have it, no islanders ever get off the see saw, and they just get on it once. If balanced, the 3rd unknown is heavy. It is a good write up though. Are there basic weighing puzzles requiring adaptive strategies? The exciting catch? Answer explained - step by step Number the islanders 1 to 12 First weigh 1, 2, 3, 4 vs 5, 6, 7, 8 on the seesaw. There are 12 men on an island. Each step here corresponds to one weighing. The island has no escapes, but there is a seesaw. Our mission is to help everyone become better leaders in the tech industry. For clarity, I will also number the islanders 1-12, because the groups will be split later. If you found that the second group weigh was unequal, then weigh 9 vs 10. sideline: S1 S2 S3 S4, 2.A.1 if balanced Brooklyn 99 And The 12 Men On An Island Puzzle - Utopia Mechanicus. Try that and see where it takes you. New comments cannot be posted and votes cannot be cast. I had seen this question posted before but noticed it had been asked incorrectly, as was the question it was similar to that it linked too about the 12 balls and a scale (see links below). I later went back and refined it a little, so here it is. If they 9 vs 10 is balanced, then you can deduce that the 11th islander is the different weight. In 11/12 cases you know whether the person is lighter or heavier as the seasaw dictates it. Weigh A against B. You must use a see-saw to figure out whose weight is different, and you may only use the see-saw 3 times. {{3 remaining with known weight solution}} Since the weight is known, all you need to do is measure 2 men from the remaining 3 against each other. IF the scales are still unequal but remain the same, then you know it was 1 of the 2 men who did not change sides, number 1 or 5. All of the islanders individually weigh exactly the same amount, except for one, who either weighs more or less than the other 11. There are no scales or other weighing device on the island. The See-Saw. Browse other questions tagged, Start here for a quick overview of the site, Detailed answers to any questions you might have, Discuss the workings and policies of this site. Looking for more great riddles? Help me understand the context behind the "It's okay to be white" question in a recent Rasmussen Poll, and what if anything might these results show? Questions: Three measurements in all. Weigh 5 against 6. Many Git commands accept both tag and branch names, so creating this branch may cause unexpected behavior. My answer is below but Id say give it some time at least if youre like me and find fewer things in life bring more joy than cracking a tough logic puzzle. There is an island with 12 islanders. (Third Use) we know it is either R1 or L1. The exciting catch? Ackermann Function without Recursion or Stack. How does a fan in a turbofan engine suck air in? ie. Put any two groups on each side of the see-saw. 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